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If a “safe C++” proposal truly proposes a safe subset, then yes your C++ code would have to opt-in to doing unsafe things. For the purposes of this discussion of a safe subset … the point is moot.
If a “safe C++” proposal truly proposes a safe subset, then yes your C++ code would have to opt-in to doing unsafe things. For the purposes of this discussion of a safe subset … the point is moot.
It’s not moot. The Safe C++ is opt-in to safety. It has to be because otherwise it wouldn’t be compatible with existing C++.
That’s a laudable difference /s. Using Rust is also an “opt-in” option.