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No. It always compares by converting to string. I actually think this is more consistent then having different behaviour if you have a string somewhere in your list.
Basically the default comparator is a.sort((a, b) =>`${a}` < `${b}` ? -1 : 1).
Only if one of them is a string right? If you have only numbers then it works fine right? Right? (Please say that I’m right 😭)
No. It always compares by converting to string. I actually think this is more consistent then having different behaviour if you have a string somewhere in your list.
Basically the default comparator is
a.sort((a, b) => `${a}` < `${b}` ? -1 : 1)
.